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in Sequences and series by (20 points)
edited by

If a,b,c are the positive integers then (a+b) (b+c) (c+a) is

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1 Answer

+1 vote
by (18.1k points)

The correct option is (B) > 8 abc

Since A.M > G.M., we have

\(\frac{a+b}2>\sqrt{ab},\frac{b+c}2>\sqrt{bc}\;and\;\frac{a+c}2>\sqrt{ac}.\)

Multiplying these inequalities, we get

(a+b) (b+c) (c+a) > 8abc.

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