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Solid `AgNO_(3)` is gradually added to a solution which is `0.01M` n `Cl^(-)` and `0.01 M` in `CO_(3)^(2-) K_(sp) AgCl=1.8x10^(-10)` and `K_(sp)Ag_(2)CO_(3)=4xx10^(-12)`
The cocentration of `Cl^(-)` when `Ag_(2)CO_(3)` starts precipating is
A. `1.8xx10^(-9)M`
B. `1.8xx10^(-5)M`
C. `1.2xx10^(-4)M`
D. `9xx10^(-6)M`

1 Answer

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Best answer
Correct Answer - D
`[Cl^(-)]=(K_(sp)AgCl)/([Ag^(+)])=(1.8xx10^(10))/(2xx10^(-5))`
`=9xx10^(-6)M`

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