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The solubility of `Ba(OH)_(2)`. `8H_(2)O` in water at `288K` is `5.6g` per `100g` of water. What is the molality hydroxide ions in saturated solution of `Ba(OH)_(2)`. `8H_(2)O` at `288K` ? [At. Mass of `Ba=137,O=16,H=1`)

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Correct Answer - `0.356m`
`2xx` moles of `Ba(OH)_(2)=` moles of `OH^(-)`
`2xx(5.6)/(315)=` moles of `OH^(-)`
molality of `OH=2xx(5.6)/(315)xx(1000)/(100)=0.356m`.

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