Correct Answer - B
For maxima `sintheta=(nlambda)/(d)`
`impliestheta=sin^(-1)((nlambda)/(d))`
So, no. of maxima in first quadrant is `(d)/(lambda)`. In second quadrant is `(d)/(lambda)`
So, in total no. of maximum `=(4d)/(lambda)` but out of these two are counted together so, actual no `=(4d)/(lambda)-2`