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If the sum of the first ten terms of the series (1 3/5)^2 + (2 2/5)^2 + (3 1/5)^2 + 4^2 + (4 4/5)^2 + ....... is 16m/5, then m is equal to

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in Mathematics by (40.7k points)

If the sum of the first ten terms of the series (1 3/5)2 + (2 2/5)2 + (3 1/5)2 + 42 + (4 4/5)2 + ....... is 16m/5, then m is equal to

(a) 102

(b) 101

(c) 101

(d) 99

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1 Answer

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Best answer

Correct option (b) 101

Explanation:

Let S10 be the sum of first ten terms of the series. Then, we have

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