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+2 votes
30.4k views
in Chemistry by (56.2k points)

On the basis of the following thermochemical data :
(Δf G° H+(aq) = 0).
H2O(l) → H+(aq) + OH(aq)ΔH = 57.32kJ
H2(g)+ 1/2O2(g) →H2O(l)ΔH = − 286.2kJ
The value of enthalpy of formation of OH– ion at 25°C is

(a) – 22.88kJ 

(b) – 228.88kJ

(c) + 228.88kJ 

(d) – 343.52kJ

1 Answer

+3 votes
by (78.5k points)
selected by
 
Best answer

Correct option (b) – 228.88kJ

Explanation:

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