Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
695 views
in NEET by (2.4k points)
Answer is  Option d) A3B4. Please make it correct.
related to an answer for: In a solid having the Nacl structure.

Please log in or register to answer this question.

1 Answer

0 votes
by (266k points)

According to NaCl structure  

so 'A' occupies 8 corners of the cubic unit cell which contribute 1/8 each to this cube  

 therefore 8*1/8 = 1   

also 6 face centered atoms contribute 1/2 to this cube   

therefore 6*1/2=3   

Therefore total contribution of atom'A' is 4   

Now B occupies octahedral voids(NaCl structure) which contribute 1/4  

 therefore 1+12*1/4 = 4   

So the formula is A4B4 or AB   

Now you are removing all the face centered atoms along one axis(any axis origin atcentre of cube)   

so the number of atoms removed from cube are 2   

so contribution from 'A' remains 8*1/8(corner atoms) + 4*1/2(facecentered atoms) = 3   

so the resultant becomes A3B4

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...