Comparing the equation
2x2 + xy - y2 + x + 4y - 3 = 0 with
ax2 + 2hxy + by2 + 2gx + 2fy + c - 0, we get,
a = 2, h = 1/2 , b = -1, g = 1/2 , f = 2, c = – 3.
Taking 1/2 common from each row, we get,
= 1/8 [4(12 —16) — 1( —6 — 4) + 1(4 + 2)]
= 1/8 [4( – 4) – 1(-10) + 1(6)]
= 1/8 (—16 + 10 + 6) = 0
Also, h2 – ab = \(\left(\cfrac{1}{2}\right)^2\) – 2 (-1) = \(\cfrac{1}{4}\) + 2 = \(\cfrac{9}{4}\) > 0
∴ the given equation represents a pair of lines. Let θ be the acute angle between the lines