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Show the equation 2x2 + xy – y2 + x + 4y – 3 = 0 represents a pair of lines. Also find the acute angle between them.

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Comparing the equation

2x2 + xy - y2 + x + 4y - 3 = 0 with

ax2 + 2hxy + by2 + 2gx + 2fy + c - 0, we get,

a = 2, h = 1/2 , b = -1, g = 1/2 , f = 2, c = – 3.

Taking 1/2 common from each row, we get,

= 1/8 [4(12 —16) — 1( —6 — 4) + 1(4 + 2)]

= 1/8 [4( – 4) – 1(-10) + 1(6)]

= 1/8 (—16 + 10 + 6) = 0

Also, h2 – ab = \(\left(\cfrac{1}{2}\right)^2\) – 2 (-1) = \(\cfrac{1}{4}\) + 2 = \(\cfrac{9}{4}\) > 0

∴ the given equation represents a pair of lines. Let θ be the acute angle between the lines

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