Comparing the given equation with
ax2 + 2hxy + by2 + 2gx + 2fy + c = 0,
we get, a = 1, h = 3/2, b = 2, g = 1/2, f= 1/2, c = k.
Now, given equation represents a pair of lines.
Taking out 1/2 common from each row , we get,
∴ 2(8k – 1) – 3(6k + 1) + 1(-3 – 4) = 0
∴ 16k – 2 – 18k – 3 – 7 = 0
∴ -2k – 12 = 0
∴ -2k = 12
∴ k = -6.