An oil drop of charge of 2 electrons fall freel with as terminal speed. Calculate the mas of oil drop so, it can move upward with same terminal speed, if electric field of `2xx10^(3) V//m` is applied.
A. `3.0xx10^(-17)kg`
B. `3.2xx10^(-17)kg`
C. `2.5xx10^(-17)kg`
D. `3.3xx10^(-17)kg`