Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
79 views
in Physics by (60.2k points)
closed by
A tuning fork A of frequency 512 Hz produces 4 beats per second when sounded with a tuning frok B. Dut to filling of the prongs of the tuning for B, the number of the beats per second becomes 6. The actual frequenct of B is
A. 517 Hz
B. 509 Hz
C. 513 Hz
D. None of these

1 Answer

0 votes
by (66.3k points)
selected by
 
Best answer
Correct Answer - A
Due to filling, frequency of tuning fork B increases. Since, after filling beats frequency increases,
`because" "f_(B) gt f_(A)thereforef_(B)-f_(A)=4`
`therefore" "f_(B)+f_(A)=4+512=216Hz`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...