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in Physics by (78.6k points)
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A constant external torque `tau` acts for a very brief period `/_ ` on a rotating system having moment of inertia `I` then
A. The angular momentum of the system will change by `tau Delta t`
B. The angular velocity of the system will change by `(tau Delta t)/I`
C. If the system was intially at rest, it will acquire rotational kinetic anergy `(tau Delta t)^(2)/(2I)`
D. The kinetic energy of the system will change by `(tau Delta t)^(2)/I`

1 Answer

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by (83.1k points)
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Best answer
Correct Answer - A::B::C
`Iomega=tauDeltat`
hence `1/2Iomega^(2)=(tauDeltat)^(2)/(2I)`

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