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If lambda is the wavelength of hydrogen atom from the transition `n=3 to n=1`,then what is the wavelength for doubly ionised lithium ion for same transition?
A. `lambda/3`
B. `3lambda`
C. `lambda/9`
D. `9lambda`

1 Answer

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Correct Answer - C
For wavelength ,`1/lambda=RZ^(2)((1)/n_(1)^(2)-(1)/n_(2)^(2)) `
Here,transition is same
So,`lambdapropto 1/Z^(2) `
`lambda_(H)/lambda_(Li)=(Z_(LI))^(2)/(Z_(H))^(2)=(3)^(1)/(1)^(2)=9`
Rightarrow` lambda_(Li)=lambda_(H)/9=lambda/9`

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