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Let f(x) = x^2 + 1/x^2 and g(x) = x - 1/x, x ∈ R -{-1, 0,1}. If h(x) = f(x)/g(x), then the local minimum value of h(x) is

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Let f(x) = x2 + 1/x2 and g(x) = x - 1/x, x ∈ R -{-1, 0,1}. If h(x) = f(x)/g(x), then the local minimum value of h(x) is

(a) 3

(b) -3 

(c) -2√2

(d) 2√2

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Correct option (d) 2√2

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