Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
95 views
in Mathematics by (78.6k points)
closed by
Sixteen players `P_(1),P_(2),P_(3)….., P_(16)` play in tournament. If they grouped into eight pair then the probability that `P_(4)` and `P_(9)` are in different groups, is equal to
A. `7/15`
B. `14/15`
C. `2/15`
D. `4/15`

1 Answer

0 votes
by (83.1k points)
selected by
 
Best answer
Correct Answer - B
Total ways `=(16!)/((2!)^(8)8!)`
Number of ways in which `P_(4)` and `P_(9)` are in same groups `=(14!)/((2!)^(7)7!)`
Number of ways in which they are in different groups
`=(16!)/((2!)^(8)8!)-(14!)/((2!)^(7)7!)`
`=(14!)/((2)^(7)7!)((15.16)/(2.(8))-1)=(14.14!)/((2)^(7)7!)`
Probability `=((14.14!)/((2)^(7).7!))/((16!)/((2)^(8)8!))=(14.8.2)/(15.16)=14/15`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...