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When excess of `SnCl_(2)` is added to a solution of `HgCl_(2)`, a white precipitate turning to gray is obtained. The grey colour is due to

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When excess of `SnCl_(2)` is added to a solution of `HgCl_(2)`, a white precipitate turning to gray is obtained. The grey colour is due to
A. `Hg_(20Cl_(2)`
B. `SnCl_(4)`
C. Sn
D. Hg
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Correct Answer - D
`SnCl_(2)+underset(("Excess"))(HgCl_(2))rarrunderset(("grey""))(Hg)+SnCl_(4)`
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