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`CuSO_(4)` reacts with KCN to form
A. `Cu(CN)_(2)`
B. `CuCN`
C. `K_(2)[Cu(CN)_(4)]`
D. `K_(3)[Cu(CN)_(4)]`

1 Answer

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Best answer
Correct Answer - B,D
`(B)` and `(D)`
`2CuSO_(4)+4KCNrarr2CuCN+2K_(2)SO_(4)+(CN)_(2)`
`3KCN+CuCNrarr K_(3)[Cu(CN)_(4)] `

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