Correct Answer - B,C,D
`underset("Blue")(CuSO_(4).5H_(2)O)overset("exposes")(hArr)overset("Pale Blue")(CuSO_(4).)3H_(2)Ooverset("100^(@)C")(hArr) underset("bluish white")(CuSO_(4).H_(2)O)overset(230^(@)C)(hArr)underset("white")(CuSO_(4))underset(Delta)overset(720^(@)C")(hArr)CuO+SO_(2)+(1)/(2)O_(2)`
Hence `A=CuO,B=SO_(2),X=230^(@)C`