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`CuSO_(4)` decolourises on addition of `KCN`, the product is
A. `Cu^(2+)` get reduced to form `[Cu(NH)_(4)]^(3-)`
B. `[Cu(CN)_(4)]^(2-)`
C. CuCN
D. `Cu(CN)_(2)`

1 Answer

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Best answer
Correct Answer - A
`CuSO_(4)+2KCN rarrCu(CN)_(2)+K_(2)SO_(4)`
`underset("unstable")(Cu(CN)_(2))hArr CuCNj+(1)/(2)(CN)_(2)`
`CuCN+3KCNhArr underset("colourless")(K_(3)[Cu(CN)_(4)]^(3-))`

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