Question

3.4 g H₂O₂ is dissolved in 448 mL solution. The
solution will be labelled as (V = Vol. strength):-

A) 0.224V

B) 5V

C) 2.5V

D) 20V

Answer 1

Strength of H₂O₂ = \(\frac{Weight\,of\,H_2O_2}{Volume\,of\,solution(L)}\)

= \(\frac{3.4g\times1000}{448L}\)

= 7.6 g/L
\(\underset{(2\times34g)}{2H_2O_2}\longrightarrow2H_2O+\underset{(22.4L)\,at\,NTP}{O_2}\) 

68 g of H₂O₂ produces 22.4 litres at oxygen gas at NTP.

Therefore, 

7.6g of H₂O₂ will produce

= 22.4/68 x 7.6

= 2.5 litre at oxygen.

Thus, volume strength of given H₂O₂ solution is 2.5

Hence, option(c) is Right answer.