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If the angle between lines represented by ax2 + 2hxy + by2 = 0 is equal to the angle between lines represented by 2x2 – 5xy + 3y2 = 0 then show that 100(h2 – ab) = (a + b)2 .

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The acute angle θ between the lines ax2 + 2hxy + by2 = 0 is given by

Comparing the equation 2x2 – 5xy + 3y2 = 0

with ax2 + 2hxy + by2 = 0, we get,

a = 2, 2h= -5, i.e. h = -5/2 and b = 3

Let ∝ be the acute angle between the lines

2x2 – 5xy + 3y2 = 0.

This is the required condition.

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