Consider 3x2 – 4xy = 0
∴ x(3x – 4y) = 0
∴ separate equations of the lines are x = 0 and 3x – 4y = 0.
Let m1 and m2 be the slopes of these lines.
Then m does not exist and and m1 = \(\cfrac{3}{4}\).
Now, required lines are perpendicular to these lines.
Since these lines are passing through the origin, their separate equations are y = 0 and
∴ their combined equation is
y(4x + 3y) = 0
∴ 4xy + 3y2 = 0.