Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
56 views
in Mathematics by (92.5k points)
closed by
`(sqrt(7)-sqrt(5))/(sqrt(7)+sqrt(5))+(sqrt(7)+sqrt(5))/(sqrt(7)-sqrt(5))` के बराबर है।
A. 12
B. `6sqrt(35)`
C. `6`
D. `2sqrt(35)`

1 Answer

0 votes
by (90.6k points)
selected by
 
Best answer
Correct Answer - A
`(sqrt(7)-sqrt(5))/(sqrt(7)+sqrt(5))+(sqrt(7)+sqrt(5))/(sqrt(7)-sqrt(5))`
`implies((sqrt(7)-sqrt(5)))/((sqrt(7)+sqrt(5)))xx((sqrt(7)-sqrt(5)))/((sqrt(7)-sqrt(5)))`
`+(sqrt(7)+sqrt(5)(sqrt(7)+sqrt(5)))/((sqrt(7)-sqrt(5))(sqrt(7)+sqrt(5)))`
`implies ((sqrt(7)-sqrt(5))^(2))/2+((sqrt(7)+sqrt(5))^(2))/2`
`implies(7+5-2sqrt(35)+7+5+2sqrt(35))/2`
`implies24/2=12`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...