Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
70 views
in Mathematics by (92.4k points)
closed by
यदि `sqrt(2)=1.4142` है तो `2sqrt(2)+sqrt(2)+1/(2+sqrt(2))-1/(2-sqrt(2))` का मान ज्ञात करें।
A. `1.4144`
B. `2.8284`
C. `28.284`
D. `2.4142`

1 Answer

0 votes
by (90.5k points)
selected by
 
Best answer
Correct Answer - B
`2sqrt(2)+sqrt(2)+1/(2+sqrt(2))-1/(2-sqrt(2))`
`implies2sqrt(2)+sqrt(2)+((2-sqrt(2)-2-sqrt(2))/((2+sqrt(2))(2-sqrt(2))))`
`implies 2sqrt(2)+sqrt(2)+(-2sqrt(2))/(4-2)`
`implies2sqrt(2)+sqrt(2)-(2sqrt(2))/2`
`implies2sqrt(2)+sqrt(2)-sqrt(2)implies2sqrt(2)`
`implies2xx1.4142=2.8284`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...