Question

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10¹⁰ Hz and amplitude 48 V m^−1.
(a) What is the wavelength of the wave?
(b) What is the amplitude of the oscillating magnetic field?
(c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 × 10⁸ m s⁻¹.]

Answer 1

Frequency of the electromagnetic wave, ν = 2.0 × 10¹⁰ Hz
Electric field amplitude, E0 = 48 V m⁻¹
Speed of light, c = 3 × 10⁸ m/s
(a) Wavelength of a wave is given as: