Question

A small body of maas 0.3 kg ascillates in vertical plane with the help of a string 0.5 m long with a constant speed of 2 m/s. It makes an angle of `60^(@)` with the vertical. Calculate tension in the string `(g=9.8m/s^(2))`.

Answer 1

Given m=0.3 kg, r=l=0.5m, v=2 m/s and `theta=60^@)`
`:.` Tension in the string `=(mv^(2))/(r)+mgcostheta`
`=(0.3xx4)/(0.5)+0.3xx9.8xxcos60^(@)`
`=2.4+1.47`
`=3.87N`.