# A uniform solid sphere has radius 0.2 m and density 8xx10^(3)kg//m^(2). Fing the moment of inertia about the tangent to its surface. (pi=3.142)

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A uniform solid sphere has radius 0.2 m and density 8xx10^(3)kg//m^(2). Fing the moment of inertia about the tangent to its surface. (pi=3.142)

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We have, redius (R) =0.2 m and density (p)=8xx10^(3)kg//m^(2)
Moment of inertia about the tangent to its surface,
I=I_(C)+MR^(2)
[ using parallel axis theorem]
(2)/(5)MR^(2)+MR^(2)
=(7)/(5)MR^(2)" "......(i)
But, Mass (M) =Volume (V)xx Density (p)
M=V_(p)=((4)/(3)piR^(3))p
Putting the value of M ing (i), we get
I=(7)/(5)((4)/(3)piR^(3))pR^(2)
=(28)/(15)piR^(5)p
=(28)/(15)xx3.142xx(2xx10^(-1))^(5)xx8000