# Three capacitors of capacities 8muF,8muFand4muF are connected in a series and a potential difference of 120 volt is maintained across the combinatio

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Three capacitors of capacities 8muF,8muFand4muF are connected in a series and a potential difference of 120 volt is maintained across the combination. Calculate the charge on capacitor of capacity 4muF.

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Let the capacitors be C_(1)=8muF,C_(2)=8muFandC_(3)=4muF.
All the capacitors are connected in series, so, the equivalent capacitance C_(s) can be calculated as
(1)/(C_(s))=(1)/(C_(1))+(1)/(C_(2))+(1)/(C_(3))
(1)/(C_(s))=(1)/(8)+(1)/(8)+(1)/(4)
(1)/(C_(s))=(1+1+2)/(8)
C_(s)=2muF
In series combination,
Q_(1)=Q_(2)=Q_(3)
But Q=C_(s)V
:. Charge on capacitor of capacity 4muF can be calculated as
Q=2xx10^(-6)xx120
=240xx10^(-6)C=240muC