Correct Answer - C
Given,`3sin^2x-7sinx+2=0`
`(3sinx-1)(sinx-2)=0`
`rArr sinx=(1)/(3) or 2`
`rArr sinx=(1)/(3) [because sinx=2]`
Let `sin^(-1)(1)/(3)=alpha,0lt alpha lt (pi)/(2)`, then `alpha,pi-alpha,+alpha,3pi-alpha,4pi+alpha,5pi-alpha` are the solution in `[0,5pi]`
Hence,required number of solutions are 6.