Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
762 views
in Mathematics by (92.5k points)
closed by
Equation of the line passing through the point (0,1,2) and equally inclined to the coordintate axes, are
A. x=y-1=z-2
B. x=y+1=z+2
C. `x/0=y/3=z/2`
D. None of these

1 Answer

0 votes
by (90.6k points)
selected by
 
Best answer
Correct Answer - A
Since, the line is equally inclined, therefore `l-m=n=cos theta`
Now, equation of a line passing through the point (0,1,2) and having direction cosine `(cos theta, cos theta, cos theta)` is
`(x-0)/(cos theta)=(y-1)/(cos theta)=(z-2)/(cos theta)`
`Rightarrow x=y-1=z-2`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...