Question

The number of electrons required to reduced ` 4.5 xx 10^(-5)g` of Al is
A. ` 1.03xx10^(18)`
B. `3.01 xx 10^(18)`
C. `4.95 xx 10^(26)`
D. `7.31 xx 10^(20)`

Answer 1

Correct Answer - B
`underset(27)(Al^(3+)) +3e^(-) to underset(27g)(Al)`
27 g of Al is reduced by `=3 xx 6.023xx10^(23)e^(-)s`
` 4.5xx10^(-5)` g of Al will be reduced by
`=(3xx6.023xx10^(23) xx 4.5xx10^(-5))/(27)`
`=3.01 xx 10^(18)` electrons