Let P be the point on the parabola, y2 = 8x, which is at a minimum distance from the centre C of the circle x2 + (y + 6)2 = 1. Then, the equation of the circle, passing through C and having its centre at, P is
(a) x2 + y2 - 4x + 8y + 12 = 0
(b) x2 + y2 - x + 4y - 12 = 0
(c) x2 + y2 - x/4 + 2y - 24 = 0
(d) x2 + y2 - 4x + 9y + 18 = 0