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The length and diameter of a metal wire is doubled the fundamental frequency of vibration will change from n to (tension being kept constant and material of both the wires is same)
A. `(n)/(4)`
B. `(n)/(8)`
C. `(n)/(12)`
D. `(n)/(16)`

1 Answer

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Best answer
Correct Answer - a
Frequency of vibration in the wire
`v=1/2 sqrt(T)/(mu)`
from Eqs (i) and (ii) we get
`=(2I)/(I)xxsqrt(r )/(r )^(2)=2xx(r )/(r )=2xx2=4`
`rarr v=n = 4v rarr v= (v)/(4)`

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