Question

The differeence in the effective capacity of two similar capacitor when joined in series and then in paralllel is 6 `mu` F the capacity of each capacitor is
A. `2 mu F`
B. `4 mu F`
C. `8 mu F`
D. `16 mu F`

Answer 1

Correct Answer - a
When two similar capactors are joined in series then effective capacity is
`(1)/(C_(s))=(1)/(c )+(1)/(C )+(1)/(C )=(2)/(C )`
`therefore C_(s)=(C )/(2)`
when capacitors are joined in parallel then `C_(p)=C+C=2C`
since `C_(p)-C_(s)=6 mu f`
`therefore 2c-(C )/(2)=6 rarr 4C-c =12`
or C=4 muF`