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In a trapezium ABCD, AB// CD and AB =2 CD. If the area of triangle AOB = 84 cm, then the area of triangle COD is:

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In a trapezium ABCD, AB// CD and AB =2 CD. If the area of triangle AOB = 84 cm, then the area of triangle COD is:
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1 Answer

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by (18.1k points)

It is given that ABCD is a trapezium and AB ∣∣ DC.

We know that the arc of similar triangles are proportional to squares of their corresponding altitude, therefore with Ar(△AOB) = 84 cm2 and AB = 2CD,

we have,

Hence, area of △COD is 21 cm2.

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