Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
11.3k views
in Physics by (88.8k points)
closed by
It is found experimentally that `13.6 eV` energy is required to separated a hydrogen atom into a proton and an electron. Compute the orbital radius and velocity of electron in a hydrogen atom.

1 Answer

+1 vote
by (87.5k points)
selected by
 
Best answer
Total energy of the electron in hydrogen atom is - 13.6 eV = `13.6 xx1.6 xx10^(-19)J=-22xx10^(-18)J` Thus from Eq. (12.4), we have `-(e^(2))/(8piepsilon_(0 )r)=-2.2 xx 10^(-18) J`
This gives the orbital radius
`r=-(e^(2))/(8piepsilon_(0)E)=-((9xx10^(9)Nm^(2)//C^(2))(1.6 xx 10^(-19)C)^(2))/((2)(-2.2xx10^(-18)J))`
= `5.3 xx 10^(-11)m`.
The velocity of the revolving electron can be computed from Eq. (12.3) with m = `9.1 xx 10^(-31) kg`,
`upsilon=(e)/(sqrt(4piepsilon_(0)mr))=2.2 xx 10^(6)m//s`.
by (20 points)
What is 9×10^9
by (10 points)
It is k=1/4πepsilon° which is 9×10^9

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...