Question

Find the reduced form of the ratio of the first quantity to second quantity.

i.  700,  308 

ii.  14,  12 and 40 paise 

iii. 5 litres, 2500 ml

Answer 1

i. ₹ 700, ₹ 308

Ratio =\(\frac{700}{308} \) =\(\frac{28\times25}{28\times11} \) =\(\frac{25}{11} \) = 25 : 11

ii. 14, 12 and 40 paise

14 = 14 x 100 paise = 1400 paise 

12 and 40 paise = 12 x 100 paise + 40 paise

= (1200 + 40) paise 

= 1240 paise

\(\therefore\) Ratio  =\(\frac{14}{12\,and \,40 \,paise} \) = \(\frac{1400\,paise}{1240\,paise} \) 

= \(\frac{1400}{1240} \) = \(\frac{40\times35}{40\times31} \) = \(\frac{35}{31}\) = 35:31 

iii. 5 litres, 2500 ml 

5 litres = 5 x 1000 ml = 5000m

 \(\therefore\) Ratio =\(\frac{5\,litres}{2500\,ml} \) = \(\frac{5000\,ml}{2500\,ml} \) = \(\frac{5000}{2500}\)

= \(\frac{2500\times2}{2500\times1} \) = \(\frac{2}{1}\)= 2:1