Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
83 views
in Physics by (87.5k points)
closed by
Suppose a pure Si-crystal has `5xx10^(28) "atoms" m^(-3)`. It is doped by 1 ppm concentration of pentavalent As. Calculate the number of electrons and holes. Give that `n_(i)=1.5xx10^(16)m^(-3)`.

1 Answer

+1 vote
by (88.8k points)
selected by
 
Best answer
Note that thermally generated electrons `(n_(i) ~10^(16) m^(–3))` are negligibly small as compared to those produced by doping.
Therefore, `n_(e)approxN_(D)`.
Since `n_(e)n_(h) = n_(i)^(2)`, The number of holes
`n_(h) = (2.25 × 10^(32))//(5 ×10^(22))
~ 4.5 × 10^(9) m^(–3)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...