Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
50 views
in Physics by (87.5k points)
closed by
At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is `100 m^(3) s^(-1)`. If the turbine generator efficiency is 60%, estimate the electric power available from the plant `(g = 9.8 ms^(-2))`.

1 Answer

0 votes
by (88.8k points)
selected by
 
Best answer
Height of water pressure head, h=300m
volume of water flow per second, `V=100m^(3)//s`
Efficiency of turbine generator, n=60% =0.6
Accelration due to gravity, g=`9.8m//s^(2)`
Density of water, `rho=10^(3)kg//m^(3)`
Electric power available from the plant`=etaxxhpgV`
`0.6xx300xx10^(3)xx9.8x x100`
`=176.4xx10^(6)W`
`=176.4MW`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...