(i) Both w-hexane and n-octane are non-polar. Thus, the intermolecular interactions will be London dispersion forces.
(ii) Both `l_(2) " and " CCl_(4)` are non-polar. Thus, the intermolecular interactions will be London dispersion forces.
(iii) `NaClO_(4)` is an ionic compound and gives `NA^(+) " and" ClO_(4)^(-)` ions in the Solution. Water is a polar molecule. Thus, the intermolecular interactions will be ion-dipole interactions.
(iv) Both methanol and acetone are polar molecules. Thus, intermolecular interactions will be dipole-dipole interactions.
(v) Both `CH_(3)CN " and " C_(3)H_(6)O` are polar molecules. Thus, intermolecular interactions will be dipole-dipole interactions.