LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
13 views
in Chemistry by (86.7k points)
closed by
Calculate the amount of benzoic acid `(C_(6)H_(5)COOH)` required for preparing `250mL` of `0.15 M` solution in methanol.

1 Answer

0 votes
by (88.1k points)
selected by
 
Best answer
0.15 M solution means than 0.15 mole of benzoic acid is dissolved in 1L of solution.
Molar mass of `C_(6)H_(5)COOH`
`=12xx6+5+12+2xx16+1=122 " g mol"^(-1)`
`therefore 0.15 " mol of " C_(6)H_(5)COOH=0.15xx122=18.3 g`
Thus, 1L or 1000 mL of solution contain
`=18.3 " g of " C_(6)H_(5)COOH`
` therefore 250 mL` of the solution will contain
`(18.3)/(1000)xx250=4.575 " g of " C_(6)H_(5)COOH`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...