Correct Answer - A
`x(x-3)=-1`
`implies (x-3)=(-1)/x`
Taking cube on both sides
`implies (x-3)^(3)=((-1)/x)^(3)`
`implies x^(3)-27-9xx(x-3)=(-1)/(x^(3))`
`implies x^(3)-27-9xx-1=(-1)/(x^(3))`
`implies x^(3)-27+9=(-1)/(x^(3))`
`implies x^(3)-18=(-1)/(x^(3))`
`implies x^(3)(x^(3)-18)=-1`
