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in Definite Integrals by (34.5k points)
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Find the area of the region bounded by the curve y = 4x2 , Y-axis and the lines y = 1, y = 4.

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By symmetry of the parabola, the required area is 2 times the area of the region ABCD. From the equation of the parabola, x2 = y/4

In the first quadrant, x > 0

∴ x = 1/2 \(\sqrt{y}\)

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