Question

3-methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is

(a) six

(b) zero

(c) two

(d) four

Answer 1

Correct Option (d) four

Explanation:

The number of stereoisomers in molecules which are not divisible into two equal halves and have n number of asymmetric C-atoms = 2ⁿ.

3-methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product i.e. 2-bromo-3-methyl pentane. lt has two chiral centres. Therefore, 4 stereoisomers are possible