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Calculate the volume of `O_(2)` and volume of air needed for combustion of `1 kg` carbon at `STP`.
A. 9333.3 litre
B. 933.33 litre
C. 93.33 litre
D. 1866.67 litre

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Best answer
Correct Answer - A
`C + O_(2) to co_(2) `
1000g
`(1000)/(2)` mole
`n_(O)_(2)` req. `=(1000)/(2)` mole
`air _(req). = (1000)/(12)xx(1)/(0.21)` mole
`(1000)(12xx0.21)xx22.4L`
=8888.8 L

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