Question

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44 u. The alkene is

(a) propene

(b) 1-butene

(c) 2-butene

(d) ethene

Answer 1

Correct Option (c) 2-butene

Explanation:

The general molecular formula for carbonyl compound is C_nH_2nO

C_nH_2nO = 44 u

C_nH_2n = 44 - 16

C_nH_2n = 28 u ⇒ n = 2

Thus, the aldehyde comes out to be C₂H₄O or CH₃CHO. ln order to ldentify an alkene, place 2 molecules of CH₃CHO with O - atom fave to face

Answer 2

Option (2)->2-butene is the answer