What is value of Boyle's temperature of ethane gas when \( a =5.489 dm ^{6} atm mol ^{-2} \) and \( b =0.0638 dm ^{3} \) atm mol" (a) \( 1048 K \) (b) \( 104.8 K \) (c) \( 209.6 K \) (d) \( 290.6 K \)

Question

What is value of Boyle's temperature of ethane gas when \( a =5.489 dm ^{6} atm mol ^{-2} \) and \( b =0.0638 dm ^{3} \) atm mol" (a) \( 1048 K \) (b) \( 104.8 K \) (c) \( 209.6 K \) (d) \( 290.6 K \)

Answer 1

Given,

a = 5.489 dm⁶ atm mol^-2

b = 0.0638 dm³

R = 0.082 L atm K^-1 mol^-1

Boyle's temp T_b = a/Rb

T_b \(=\frac{5.489}{0.082\times0.0638}\)

T_b = 1049.52 K

Option (b) is correct.