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Derive an expression for period of a conical pendulum

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1 Answer

+4 votes
by (18.1k points) 1 flag

Case III - Conical pendulum →

T sin θ = mV2/r

T cos θ = mg

\(\frac{T\,sin\,\theta}{T\,cos\,\theta}=\frac{mV^2}{r\,mg}\)

tan θ = V2/rg

Time period —

T = 2πr/V

T = \(\frac{2\pi r}{\sqrt{rg\,tan\,\theta}}\)

T = 2π \(\sqrt{\frac r{g\,tan\,\theta}}\)

by (35 points)
Plese answer in detail solved

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