Correct Answer - A::B::C::D
`(A)to(p),(B)to(s),(C)to(q),(D)to(q)`
(A) ENDEA, N,O,E,L are five different letters, then perrmutations=5!.
(B) if E is in the first and last position, then permutations
`=(7!)/(2!)=(7xx6xx5!)/(2)=21xx5!`
(C) for first four letters`=(4!)/(2!)=4xx3=12` and for last five
letters`=(5!)/(3!)=(5!)/(6)`, then permutations `=12xx(4!)/(2!)=12`, then permutations `=(5!)/(3!)xx12=(5!)/(6)xx12=2xx5!`