Question

The henrys law constant for the solubility of N₂ gas in water at 298k is 1.0×10⁵ atm. The mole fraction of N₂ in air is 0.8 . The number of moles of N₂ from air dissolved in 10moles of water of 298k and 5atm pressure  is

a)4.0×10^-4 

b)4.0×10^-5

C) 5×10^_5

d) 4×10^_6

Answer 1

10 moles of water contain = 10 × 4 × 10^-5 = 4 ×10⁻⁴  mole of N₂